Input Format
The first line contains , the number of testcases.
Each testcase contains  lines, representing time  and time .
Constraints
• Input contains only valid timestamps
• .
Output Format
Print the absolute difference  in seconds.

### Problem solution in Python 3 programming language.

from datetime import datetime

for i in range(int(input())):
t1 = datetime.strptime(input(), '%a %d %b %Y %H:%M:%S %z')
t2 = datetime.strptime(input(), '%a %d %b %Y %H:%M:%S %z')
print(abs(int((t1-t2).total_seconds())))

#### Second solution

#!/bin/python3
import math
import os
import random
import re
import sys
import datetime
# Complete the time_delta function below.
def time_delta(t1, t2):
#Getting the date, time from t1
wd1 = t1[:3]
dd1 = int(t1[3:6])
mon1 = t1[7:10]
yy1 = int(t1[10:15])
hh1 = int(t1[16:18])
mm1 = int(t1[19:21])
ss1 = int(t1[22:24])
#tm1 = t1[15:24]
#z1 = t1[26:31]
off1 = t1[25:26]
offh1 = t1[26:28]
offm1 = t1[28:30]
z1 = offh1+':'+offm1+':'+'00'
#Getting the date, time from t2
wd2 = t2[:3]
dd2 = int(t2[3:6])
mon2 = t2[7:10]
yy2 = int(t2[10:15])
hh2 = int(t2[16:18])
mm2 = int(t2[19:21])
ss2 = int(t2[22:24])
#tm2 = t2[15:24
#z2 = t2[26:31]
off2 = t2[25:26]
offh2 = t2[26:28]
offm2 = t2[28:30]
z2 = offh2+':'+offm2+':'+'00'
# List of months.
month_set = ['Dummy','Jan','Feb','Mar','Apr','May',
'Jun','Jul','Aug','Sep','Oct','Nov','Dec']
#day1 = datetime.date(yy1, month_set.index(mon1), dd1)
#day2 = datetime.date(yy2, month_set.index(mon2), dd2)
#tm1 = datetime.time(hour=hh1, minute=mm1, second=ss1,
#tm2 = datetime.time(hour=hh2, minute=mm2, second=ss2,
#Forming the timestamps
timestamp1 = datetime.datetime(yy1, month_set.index(mon1),
dd1, hour = hh1, minute=mm1, second=ss1, microsecond=0, tzinfo=None)
timestamp2 = datetime.datetime(yy2, month_set.index(mon2),
dd2, hour=hh2, minute=mm2, second=ss2, microsecond=0, tzinfo=None)
#Creating the offset in datetime format
offset1 =datetime.time(hour=int(offh1), minute=int(offm1),
second=0, microsecond=0, tzinfo=None)
offset2 =datetime.time(hour=int(offh2), minute=int(offm2),
second=0, microsecond=0, tzinfo=None)
#Calculation of the date difference because of the zone(offset)
if(off1 == '+'):
timestamp1 = timestamp1 - datetime.timedelta(
hours=int(offh1), minutes=int(offm1))
if(off1 == '-'):
timestamp1 = timestamp1 + datetime.timedelta(
hours=int(offh1), minutes=int(offm1))
if(off2 == '+'):
timestamp2 = timestamp2 - datetime.timedelta(
hours=int(offh2), minutes=int(offm2))
if(off2 == '-'):
timestamp2 = timestamp2 + datetime.timedelta(
hours=int(offh2), minutes=int(offm2))
#Finding the absolute difference:
diff = str((abs(int(((timestamp1-datetime.datetime(1970,1,1)).
total_seconds())-
((timestamp2-datetime.datetime(1970,1,1)).total_seconds())))))
return(diff)

if __name__ == '__main__':
fptr = open(os.environ['OUTPUT_PATH'], 'w')
t = int(input())
for t_itr in range(t):
t1 = input()
t2 = input()
delta = time_delta(t1, t2)
fptr.write(delta + '\n')
fptr.close()

### Problem solution in Python 2 programming language.

from datetime import datetime

for i in range(int(raw_input())):
t1 = datetime.strptime(raw_input(), '%a %d %b %Y %H:%M:%S %z')
t2 = datetime.strptime(raw_input(), '%a %d %b %Y %H:%M:%S %z')
print abs(int((t1-t2).total_seconds()))