A Java interface can only contain method signatures and fields. The interface can be used to achieve polymorphism. In this problem, you will practice your knowledge on interfaces.

You are given an interface AdvancedArithmetic which contains a method signature int divisor_sum(int n). You need to write a class called MyCalculator which implements the interface.

divisorSum function just takes an integer as input and return the sum of all its divisors. For example divisors of 6 are 1, 2, 3 and 6, so divisor_sum should return 12. The value of n will be at most 1000.

Read the partially completed code in the editor and complete it. You just need to write the MyCalculator class only. Your class shouldn't be public.


hackerrank java interface solution

Java Interface problem solution | HackerRank

import java.util.*;
interface AdvancedArithmetic {
 public abstract int divisorSum(int n);
}

//Solution starts
class MyCalculator implements AdvancedArithmetic {
 public int divisor_sum(int n) {
  int ans = 0;
  for (int i = 1; i <= n; i++) {
   if (n % i == 0) ans += i;
  }
  return ans;
 }
}
//Solution ends


class Solution {

 public static void main(String[] argh) {
   MyCalculator my_calculator = new MyCalculator();
   System.out.print("I implemented: ");
   ImplementedInterfaceNames(my_calculator);
   Scanner sc = new Scanner(System.in);
   int n = sc.nextInt();
   System.out.print(my_calculator.divisorSum(n) + "\n");

  }
  /*
   *  ImplementedInterfaceNames method takes an object
   */
 static void ImplementedInterfaceNames(Object o) {

  Class[] theInterfaces = o.getClass().getInterfaces();
  for (int i = 0; i < theInterfaces.length; i++) {
   String interfaceName = theInterfaces[i].getName();
   System.out.println(interfaceName);
  }
 }
}