Input Format
The first line contains a single integer denoting .
Constraints
Output Format
If , then print the lowercase English word corresponding to the number (e.g., one for two for , etc.); otherwise, print Greater than 9 instead.

## Conditional Statements in C problem solution | HackerRank

#include <stdio.h>
#include <string.h>
#include <math.h>
#include <stdlib.h>

int main() {

int n;
scanf("%d", &n);
if(n == 1) {
printf("one");
}
else if(n == 2) {
printf("two");
}
else if(n == 3) {
printf("three");
}
else if(n == 4) {
printf("four");
}
else if(n == 5) {
printf("five");
}
else if(n == 6) {
printf("six");
}
else if(n == 7) {
printf("seven");
}
else if(n == 8) {
printf("eight");
}
else if(n == 9) {
printf("nine");
}
else {
printf("Greater than 9");
}

return 0;
}

### Second Solution

#include <stdio.h>
#include <string.h>
#include <math.h>
#include <stdlib.h>

int main() {

int n;
char* represent[10] = {"Greater than 9", "one", "two", "three", "four", "five", "six", "seven", "eight", "nine"};

scanf("%d", &n);

if(n > 9) {
printf("%s", represent[0]);
}
else {
printf("%s", represent[n]);
}

return 0;
}